We have been given a quadratic function 
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is 
.
If we restrict the domain of this function to either ![(-\infty,5]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%5D)
or 
, it will become one to one function.
Let us know find its inverse.
Upon interchanging x and y, we get:
Let us now solve this function for y.
Hence, the inverse function would be 
if we restrict the domain of original function to and the inverse function would be 
if we restrict the domain to .
Answer:Exact Form:
1/2
Step-by-step explanation:
Answer:
2,3,6
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
So we have the product of:
Multiply. Combine like terms:
The first term is 24.
The second term stays as it is.
The third term will equate to y^7. Recall how to multiply exponents. The base stays constant and you add the exponents. Thus:
Our answer is C.
And we're done!
