Answer:
2.8 N
Explanation:
Fp = 7.7 N
mA = 12.1 kg
mB = 7 kg
Let a be the acceleration and Fc be the contact force between A and B.
By the free body diagram, use Newton's second law
Fp - Fc = mA x a ..... (1)
Fc = mB x a ..... (2)
Adding both the equations
Fp = (mA + mB) x a
7.7 = (12.1 + 7) x a
a = 0.4 m/s^2
Substitute this value in equation (2), we get
Fc = 7 x 0.4 = 2.8 N
Thus, the contact force between the two blocks is 2.8 N.
Explanation:
The magnitude of other charge will be 1 × 10⁻² coulomb
The formula of electrostatic force is
Electrostatic force = K q1 q1 / r²
where k is the coulomb's constant whose value is 9 × 10⁹
q1 and a2 are the magnitude of charges
and r is the distance between them
magnitude of the force given to us is 9.0 × 10⁻⁵ newtons
magnitude of one charge = 1.0 × 10⁻⁶ coulomb
Force = K q1 q2 / r²
9.0 × 10⁻⁵ = ( ( 9 × 10⁹ ) × ( 1.0 × 10⁻⁶ ) × q2 ) / 1
9.0 × 10⁻⁵ = 9 × 10³ × q2
10⁻² = q2
Charge on q2 is 1 × 10⁻² coulomb
So the magnitude of the second charge is came out to be 1 × 10⁻² coulomb after applying the formula of electrostatic force.
Learn more about electrostatic force here:
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Answer:
-1.03 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S. I unit of acceleration is m/s².
Mathematically, acceleration is expressed as
a = (v-u)/t ........................ Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time.
Given: u = 13.60 m/s, v = 7.20 m/s t = 6.2 s.
Substituting into equation 2
a = (7.20-13.60)/6.2
a = -6.4/6.2
a = -1.03 m/s²
Note: a is negative because, the hockey puck is decelerating.
Hence the average acceleration = -1.03 m/s²
The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1<span>s2, </span>2<span>s2, </span>2<span>p6, </span>3<span>s2, </span>3<span>p<span>1
If three electrons are lost, then these electrons are removed from the outermost level.
In our case, electrons are removed from the third energy level (one electron is removed from the 3p orbital and two electrons are removed from the 3s orbital).</span></span>
The answer is 6.no got it right
