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3 years ago

Ashen light (or earthshine) is

Physics

1 answer:

Annette [7]3 years ago

8 0

Answer:

Explanation:

The condition known as Earth shine takes place when the reflecting sunlight from our world illuminates the Moon's dark side. This is usually the result that the dark side of the moon is showered in a dim, faint light. It is also called as the ashen light of the Moon, or in the wings of the new Moon as the old Moon.

Therefore the correct reason would be e. sunlight reflected by Earth that illuminates the "dark" portion of the Moon.

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Which of the following best describes the circuit shown below?

kifflom [539]

Answer:

A..............hope it will help you

5 0

3 years ago

A ball is hung from a rope, making a pendulum. When it is pulled 5° to the side, the restoring force is 1.0 N. What will be the

Trava [24]

Answer:

restoring force is 2 N

Explanation:

given data

angle pulled = 5°

force = 1 N

pulled = 10°

to find out

restoring force

solution

we know here force

force = m×g×sinθ ..........1

so here θ is very small so sinθ = θ

1 = mg(5)

mg = 1 /5 ..................2

and

now for 10 degree

we know here θ is small so sinθ = θ

so from equation 1

force = m×g×sinθ

put equation 2 here

force = 1/5 × 10

force = 2 N

so restoring force is 2 N

7 0

3 years ago

Based on Schaffer's arguments in "The Value of a Sherpa Life," choose the statement

Tju [1.3M]

Answer:

Sherpas do work that is much more meaningful than the work other climbers do.

Explanation:

3 0

3 years ago

If the x-position of a particle is measured with an uncertainty of 1.00×10-10 m, then what is the uncertainty of the momentum in

yawa3891 [41]

Answer:

The uncertainty in momentum is 5.25x 10^25Jsm

Explanation:

We know that

h bar = h/2π

1.05x 10^34=h/2pπ

h=1.05x 10^ 34(2π)=6.597x 10^-34Js

dp=(6.597x10^-34/4pπ)/(1x10^-10)

=5.25x10^-25 Jsm

4 0

3 years ago

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

tresset_1 [31]

Answer:

Explanation:

a. Given that:

$m-$ mass of first & second piece, $3m-$ mass of 3rd piece, $\bar v_1$ -velocity of first piece( $-23\dot i \ m/s$ ) and $\bar v_2$ as velocity of 2nd piece ( $-23\dot j \ m/s$ )

Let $\bar v_3$ be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

$m\bar v_1 +m\bar v_2 +3m \bar v_3=0$ #Dividing both sides by $m, m\neq 0$

$\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)$

#Plug the $\bar v_1 ,\bar v_2$ values:

$\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)$

#So the magnitude of the third piece is:

$|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s$

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the $x$ -axis), we find $\angle \theta$ . The angle is obtained by getting the tan inverse as:

$\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree$

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0

3 years ago