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Artist 52 [7]
3 years ago
11

Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms con

verts to 2.7 × 1017 joules (J = )
Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}
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A suit regularly cost 375.95 cents Bob buys it on sale for 268.35 cents how much does he save
Stolb23 [73]

Hello, all we need to do in this case to subtract the amount of money Bob paid for the suit from the amount of money the suit regularly costs. So:

375,95 - 268,35 = 107,6

Bob saves 107,6$.

7 0
3 years ago
I don't really understand this question so can someone please help
Makovka662 [10]
Hello,

(5x-2)+(2x+6)=67
==>7x+4=67
==>7x=67-4
==>7x=63
==>x=63/7
==>x=9
|AB|=5x-2=5*9-2=45-2=43 (miles)


8 0
3 years ago
What is the constant proportionality for y=2/3x
Lerok [7]
The constant proportionality is 2/3 because it will still be going on
for example- 2/3+2/3= 2/3*2

The number 2/3 goes 
3 0
3 years ago
Read 2 more answers
What is the solution to this equation?
Anettt [7]

Answer:

B. a = 5

Step-by-step explanation:

3(a - 4) + 1 = 9 - a

Distribute the 3 into the parenthesis.

3a - 12 + 1 = 9 - a

Add -12 and 1.

3a - 11 = 9 - a

Add a to both sides.

4a - 11 = 9

Add 11 to both sides.

4a = 20

Divide both sides by 4.

a = 5.

Proof:

3(a - 4) + 1 = 9 - a

Substitute variable.

3(5 - 4) + 1 = 9 - 5

Subtract inside parenthesis.

3(1) + 1 = 9 - 5

Multiply 3 and 1.

3 + 1 = 9 - 5

Add 3 and 1.

4 = 9 - 5

Subtract 5 from 9.

4 = 4.

6 0
3 years ago
2/(a-7)(a+2)=4/(a+3)(a+2)
pochemuha
\frac{2}{(a - 7)(a + 2)} = \frac{4}{(a + 3)(a + 2)}

\frac{2}{(a^{2} + 2a - 7a - 14)} = \frac{4}{(a^{2} + 2a + 3a + 6)}

\frac{2}{a^{2} - 5a - 14} = \frac{4}{a^{2} + 5a + 6}

2(a^{2} + 5a + 6) = 4(a^{2} - 5a - 14)
2(a^{2}) + 2(5a) + 2(6) = 4(a^{2}) - 4(5a) - 4(14)
2a^{2} + 10a + 12 = 4a^{2} - 20a - 56
2a^{2} - 2a^{2} + 10a + 12 = 4a^{2} - 2a^{2} - 20a - 56
10a + 20a + 12 = 2a^{2} - 20a + 20a - 56
30a + 12 + 56= 2a^{2} - 56 + 56
\frac{30a + 68}{2} = \frac{2a^{2}}{2}
15a + 34 = a^{2}
\sqrt{15a + 34} = a
6 0
3 years ago
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