Question

Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms converts to 2.7 × 1017 joules (J = )

Answer 1

$Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}$