Answer:
There are no vertical asympotes for this rational function.
Step-by-step explanation:
For rational functions, a vertical asymptote exists for every value of the independent variable such that function become undefined, that is, such that denominator is zero. Let be the following rational function:
, 
There is a vertical asymptote for this case:


Which is out of the interval given to the rational function. Hence, we conclude that there are no vertical asympotes for this rational function.
Answer:
isn't it 36cm^2
Step-by-step explanation:
sqaure is even so i think you do 6×6
Answer:
Step-by-step explanation:
We are given that

Function f decreases from quadrant 2 to quadrant 1 and approaches y=0
It cut the y- axis at (0,6) and passing through the point (1,2).
Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.
It passing through the point (-1,2) and cut the y-axis at point (0,6).
Reflection across y- axis:
Rule of transformation is given by

Using the rule then we get

By using

Substitute x=-1

Substitute x=0

Therefore,
is true.
Answer:
2
Step-by-step explanation:
add 1 plus 1 if you have 1 gummy and you add one you will have 2 gummies