Solve for x.

Mathematics

2 answers:

ASHA 777 [7]2 years ago

6 0

Answer:

The value of x in simplest fraction is $\frac{2}{5}$

Step-by-step explanation:

Given : Equation $x^3=\frac{8}{125}$

We have to find the value of x in simplest fraction.

Consider the given equation $x^3=\frac{8}{125}$

writing 8 as 2 × 2 ×2

and writing 125 as 5 × 5 × 5

Thus, $x^3=\frac{8}{125}=\frac{2\times 2\times 2}{5\times 5\times 5}$

re-written as $x^3=(\frac{2}{5})^3$

Comparing both side, we have,

$x=\frac{2}{5}$

Thus, The value of x in simplest fraction is $\frac{2}{5}$

d1i1m1o1n [39]2 years ago

5 0

X³ = 8/125

x = ∛8/125

x = 2/5

In short, Your Answer would be: 2/5

Hope this helps!

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Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0

solmaris [256]

$\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 = \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 = -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}$

5 0

2 years ago

5 ( n - 7 ) = 2 ( n + 14 )

wariber [46]

Answer:

n=21

Step-by-step explanation:

We must find n.

Remember PEMDAS. First we must do the Parentheses. Lets do distributive property by multiplying a number that is immediately outside the parentheses with each number inside the parentheses. Lets do this one side at a time.

First lets do 5(n - 7). We get 5n - 35

Now 2(n + 14) is 2n + 28

Okay...... now we have $5n-35=2n+28$