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ANEK [815]
3 years ago
5

△MNO ~△DEF. Identify the perimeter and area of △MNO to the nearest tenth. PLEASE HELP!!!

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

Answer: P =38.7 in, A=63.7in^2

Step-by-step explanation: start by using the formula for area of a triangle: A =bh/2 and plug in values given for the larger triangle to find the height. 115=9h/2,. 230 =9h h= 25.556

Subtract from perimeter to get an estimate of the third side: 62-34.556=27.45

Realize now that the drawing is not to scale!

Use the dimensions of the larger triangle to and the proportion 6.7/9 = smaller / larger to find other dimensions of the smaller triangle. Add the sides to get perimeter. Multiply bh/2 to get the Area. Choose the answer that is closest to your calculations as the numbers are estimated. We cannot assume that this is a right triangle.

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(8x+5)+(−x2−8)<br><br><br>I don't know what to do ​
nexus9112 [7]

Answer:

-x^{2} +8x-3

Step-by-step explanation:

8 0
3 years ago
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36.90 as a fraction what dose it equals
Soloha48 [4]
Hello!

I believe that 36.90 as a fraction would be 369/10

I hope this helps!
4 0
3 years ago
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PLS HELP! WILL GIVE BRAINLIEST
Leviafan [203]

Answer:

  • The center (2, 2.5), radius \sqrt{37} / 2

Step-by-step explanation:

<u>The standard form of the equation of a circle is: </u>

  • ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius

<u>Rewrite the given equation in the standard form:</u>

  • 2x^2 + 2y^2 - 8x + 10y + 2 = 0
  • x^2 - 4x + y^2 + 5y = -1
  • x^2 - 4x + 2^2 + y^2 + 5y + (5/2)^2 = -1 + 4 + 25/4
  • (x - 2)^2 + (y + 2.5)^2 = 37/4

<u>The center is:</u>

  • (2, 2.5)

<u>And radius is:</u>

  • <u />\sqrt{37} / 2

4 0
3 years ago
PLEASE HELP ME!!!
crimeas [40]
B=4676+10043 c=b-2160 answer equals b+c
I hope this is helpful I am trying not to say the exact answer but to teach you instead
4 0
3 years ago
I’m confused on this one
Alenkinab [10]

Remark

I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.

So DEB + DCB = 180o

DEB = 180 - 87

DEB = 93o

Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.

7 0
3 years ago
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