3 years ago

(2x-7)² i've forgotten how to solve this, please help me!!!

2 answers:

8 0

$(2x-7)^2=(2x-7)(2x-7)=2x\cdot2x+2x\cdot(-7)-7\cdot2x-7\cdot(-7)\\\\=4x^2-14x-14x+49=4x^2-28x+49\\\\\\or\\\\\\(2x-7)^2=(2x)^2-2\cdot2x\cdot7+7^2=4x^2-28x+49\\\\(a-b)^2=a^2-2ab+b^2$

eimsori [14]3 years ago

5 0

Alright, lets assume x = 5. 2 X 5 = 10 - 7 = 3, then 3 squared is 9. Ans. = 9.

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