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REY [17]
1 year ago
13

suppose we flip a fair coin five times and each time it lands heads up. the probability of landing heads up on the next flip is

. a. 1 b. .5 c. .75 d. 0
Mathematics
1 answer:
aleksley [76]1 year ago
5 0

Probability is simply how likely something is to happen, so the probability of landing heads up on the next flip is 1/2.

<h3>How is probability determined?</h3>

The probability is obtained by dividing the total number of outcomes by the entire number of potential ways an event may occur. Odds are a separate concept from probability. The probability of an event happening is divided by the probability that it won't, and the result is the odds.

<h3>What is probability?</h3>

Mathematical explanations of the likelihood that an event will occur or that a statement is true are referred to as probabilities. A value among 0 and 1 represents the likelihood of an event, with 0 generally denoting impossibility and 1 denoting certainty.

P(H)= Probability of getting  head while flipping a coin is 1/2

and,

P(T)= Probability of getting  tail while flipping a coin is 1/2

To know more about probability visit:

brainly.com/question/11234923

#SPJ4

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Answer:

l_n=3^n-1

Step-by-step explanation:

We will prove by mathematical induction that, for every natural n,  

l_n=3^n-1

We will prove our base case (when n=1) to be true:

Base case:

As stated in the qustion, l_1=2=3^1-1

Inductive hypothesis:  

Given a natural n,  

l_n=3^n-1

Now, we will assume the inductive hypothesis and then use this assumption, involving n, to prove the statement for n + 1.

Inductive step:

Let´s analyze the problem with n+1 stones. In order to move the n+1 stones from A to C we have to:

  1. Move the first n stones from A to C (l_n moves).
  2. Move the biggest stone from A to B (1 move).
  3. Move the first n stones from C to A (l_n moves).
  4. Move the biggest stone from B to C (1 move).
  5. Move the first n stones from A to C (l_n moves).

Then,

l_{n+1}=3l_n+2.

Therefore, using the inductive hypothesis,

l_{n+1}=3l_n+2=3(3^n-1)+2=3^{n+1}-3+2=3^{n+1}-1

With this we have proved our statement to be true for n+1.    

In conlusion, for every natural n,

l_n=3^n-1

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Step-by-step explanation:

4 0
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Given trapezoid abcd with bases ab and cd, draw diagonals ac and bd. let e be the midpoint of ac and f the midpoint of bd. prove
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Consider the picture.

Let MN be the midsegment of the trapezoid.

That is M is the midpoint of AD, N is the midpoint of BC.

Being the midsegment of the trapezoid, MN is parallel to the bases.


Let O and K be the intersections of the diagonals with the midsegment.




MN//AB, so MO//AB, and since M is the midpoint of DA, O must be the midpoint of DB, 

Similarly we prove that K is the midpoint of CA.

Thus O is F and K is E.

O and K lie on the midsegment MN, so F and E lie on the midsegment.



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Answer:

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Step-by-step explanation:

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