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crimeas [40]
3 years ago
5

Frankie is practicing for a 5−kilometer race. His normal time is 31 minutes 25 seconds. Yesterday it took him only 29 minutes 38

seconds. How much faster was Frankie yesterday than his normal time?
Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0
Frankie was 107 seconds faster or 1 minute and 47 seconds faster
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Hey guys! Leave the answer in terms of pi :)
DaniilM [7]
A) if the diameter is 13 the radius is 6.5
(6.5 \times 6.5) \times \pi = 42.25\pi  \\  =  132.7323
b)if the diameter is 6 the radius will be 3
(3 \times 3) \times \pi = 9\pi  \\ = 28.27433
hope this helps
8 0
3 years ago
Plz help asap! I will give 35 points for next question THANKS!
Troyanec [42]

k is the shift up and down

so  to shift it down K < 0

h is the shift left and right

a positive shifts left

h>0

Choice C

5 0
3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

5 0
3 years ago
Read 2 more answers
HELP!!!!!
schepotkina [342]

<u>Answer:</u>

The correct answer option is B.

<u>Step-by-step explanation:</u>

We are given a graph with different intervals A, B, C and D and we are to figure out whether which of these intervals on the graph can be describes as linear increasing.

From the given interval options, we can see that C is constant while the intervals A and D are decreasing linear.

Its the interval B which can be describes as linear increasing since it has a positive slope.

3 0
3 years ago
Read 2 more answers
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