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olga55 [171]
3 years ago
7

5ABCD is a quadrilateral. AO and BO are the angle bisectors of A

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:

60°

Step-by-step explanation:

sum of interior angles of quadrilateral is 360°

∠C = 70°

∠D = 50°

∠C + ∠D = 120°

∴ ∠A + ∠B = 360° - 120° =240°

AO and BO bisect ∠A and ∠B

∠OAB + ∠OBA = 1/2 x ( ∠A + ∠B) = 120°

∠AOB = 180° - (∠OAB + ∠OBA) = 180° - 120° = 60°

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What is the value of X in the equation 2x+3y=36, when y=6?
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Can you solve 27,28,39,30,31,32,33,34?
kozerog [31]

Answer:

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Step-by-step explanation:

27. \:  \:  \frac{ {x}^{ - 1} }{ {x}^{ - 8} }  \\  \frac{ {x}^{8} }{ {x}^{1} }  \\  {x}^{8 - 1}   =  {x}^{7} \\

28. \:  \:  \:  \frac{ {52x}^{6} }{ {13x}^{ - 7} }  \\   \frac{ {52x}^{6}  {x}^{7} }{13}  \\  {4x}^{6 + 7}  =  {4x}^{13}

29. \:  \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\  {f}^{( - 3) +2 + ( - 3) }  \\  {f}^{ - 4}  \\  \frac{1}{ {f}^{4} }  \\

30. \:  \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\   \frac{ {x}^{9} }{ {x}^{4} }  \\  {x}^{9 - 4}  =  {x}^{5}

31. \:  \:  \frac{ {24x}^{6} }{ {12x}^{ - 8} }  \\  \frac{ {24x}^{6} {x}^{8}  }{12}  \\  {2x}^{6 + 8}  =  {2x}^{14}  \\

32. \:  \:  \frac{ {3x}^{2}  {y}^{ - 3} }{ {12x}^{6}  {y}^{3} }  \\  \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3}  {y}^{3}  }  \\  \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} }  \\  \frac{ {x}^{ - 4} }{ {4y}^{6} }  \\  \frac{1}{ {4y}^{6}  {x}^{4} }  = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }

33. \:  \:  {( {2x}^{3}  {y}^{ - 3}) }^{ - 2}  \\ {2x}^{3 \times  - 2}  {y}^{ - 3 \times  - 2}  \\  {2x}^{ - 6}  {y}^{6}  \\  \frac{ {2y}^{6} }{ {x}^{6} }  \\  {( \frac{2y}{x} )}^{6} \\

4 0
2 years ago
Another one help please
guapka [62]

there must be subtraction of multiplication of each two diagonal,

|G|=[12×2-(-6)×0]

=(24+0)

=24ans

8 0
4 years ago
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