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Stells [14]
3 years ago
9

What is the value of B after the equation A=3/7(B-25)

Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0
If your equation is A = 3(B-25)/7, then we can solve for B by isolating B on one side. We can do this by the following...

First, multiply both sides by 7
7A = 3(B-25)

Next, divide both sides by 3.
7A/3 = B - 25

Finally, add 25 to both sides.
7A/3 + 25 = B

Therefore, B = 25 + 7A/3
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Help Asap! 20 points!
dybincka [34]
D = 10 is the diameter so r = d/2 = 10/2 = 5 is the radius

Plug r = 5 and h = 7 into the formula below and simplify
V = pi*r^2*h
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4 0
3 years ago
What is the value of x in the diagram?
dalvyx [7]

Answer:

x = 30

Step-by-step explanation:

here 50 is hypotenuse as it is opposite of 90 degree.

x and x + 10 are the two other smaller sides of a right angled triangle respectively.

using pythagoras theorem,

a^2 + b^2 = c^2

x^2 + (x + 10)^2 = 50^2

x^2 + x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 - 2500 = 0

2x^2 + 20x - 2400 = 0

2(x^2 + 10x - 1200) = 0

x^2 + 10x - 1200 = 0

x^2 + (40 - 30) - 1200 = 0

x^2 + 40x - 30x - 1200 = 0

x(x + 40) - 30(x + 40x) = 0

(x + 40)(x - 30) = 0

either x + 40 = 0          OR x - 30 = 0

x = 0 - 40

x = -40

x - 30 = 0

x = 30

x = -40,30

since the length and distance is not measured in negative ur answer will be 30

credit goes to sreedevi102

thank u very much . At first i was wrong and giannathecookie i m really sorry

3 0
3 years ago
Read 2 more answers
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