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Nadusha1986 [10]
3 years ago
13

Complete the table by filling in the initial amount and the percentage of growth or decay for each exponential equation.

Mathematics
1 answer:
kari74 [83]3 years ago
8 0
Tha part



Explanation:




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horrorfan [7]

The coldest temperature is the negative value furthest away from 0.

-10 would be the answer.

7 0
4 years ago
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This is math. i need help bc i do not understand this
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3 0
4 years ago
What is the area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48
Nesterboy [21]

Answer:

The area of cylinder 949.536 in²

Step-by-step explanation:

Points to remember

Curved surface area of cylinder = 2πrh

Where r - radius of cylinder

h - Height of cylinder

<u>To find the area of cylinder</u>

Here r = diameter/2 = 6.3/2 = 3.15 in

h = 48 in

Area =  2πrh

 = 2 * 3.14 * 3.15 * 48

= 949.536 in²

Therefore area of cylinder 949.536 in²

4 0
3 years ago
Z varies directly with x and inversely with y. When x=6 and y=2, .z=15. Write function that models variation. Then, find z when
tester [92]
\bf \begin{array}{cccccclllll}&#10;\textit{direct proportional variation}\\\\\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&#10;\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&#10;y&=&{{ k}}&\cdot&x&#10;\\&#10;&&  y={{ k }}x&#10;\end{array}\\ \quad \\


\bf \textit{inverse proportional variation}\\\\&#10;\begin{array}{llllll}&#10;\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\&#10;\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\&#10;y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}&#10;\\&#10;&&y=\cfrac{{{  k}}}{x}&#10;\end{array}


\bf \\\\&#10;-------------------------------\\\\&#10;\textit{z varies directly with x}\implies z=kx&#10;\\\\&#10;\textit{and inversely with y}\implies z=\cfrac{kx}{y}&#10;\\\\\\&#10;\textit{we also know that}\quad &#10;\begin{cases}&#10;x=6\\&#10;y=2\\&#10;z=15&#10;\end{cases}\implies 15=\cfrac{k\cdot 6}{2}\implies 30=6k

\bf \cfrac{30}{6}=k\implies \boxed{5=k}\impliedby \textit{constant of variation}&#10;\\\\\\&#10;thus\implies z=\cfrac{5x}{y}\\\\&#10;-------------------------------\\\\&#10;\textit{what's "z" when }&#10;\begin{cases}&#10;x=4\\&#10;y=9&#10;\end{cases}\implies z=\cfrac{5\cdot 4}{9}
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4 years ago
What form is 3x-2y=4
VLD [36.1K]
Standard form is the form I believe
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