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xenn [34]
3 years ago
9

Nia is 3 years younger than Jordan. Jordan is 36 years old.

Mathematics
2 answers:
slava [35]3 years ago
4 0
Well it's 33. The 5 step problem thing I'm not to sure of.
Triss [41]3 years ago
4 0

Answer:

B. 33 years.

Step-by-step explanation:

Let N represent Nia's age in years.

We have been given that Nia is 3 years younger than Jordan. So Jordan's age would be 3 years more than Nia's age that is N+3 years.

We are told that Jordan is 36 years old.  We can represent this information in an equation as:

N+3=36

N+3-3=36-3

N=33

Therefore, Nia's age is 33 years.

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Please help ASAP! Show work please! I will give brainliest!
kirill [66]

-4x/7 > 10

Multiply both sides by 7:

-4x > 70

Divide both sides by -4"

x > 70 / -4

Simplify the fraction:

70/-4 = 35 / -2


Because the fraction is negative you need to reverse the inequality sign:

x < -35/2


The answer is the first one: {x|x < -35/2}

4 0
3 years ago
Lilah completed the division problem below.
victus00 [196]
A - False

B - True

C - True

D - False

E - True

-----
7.84 / 2 = 3.92
6 0
3 years ago
Martin is two years younger than three times his daughter Ada’s age. The sum of their ages is 54. If Ada’s age is given by a, th
liq [111]

Answer:

A. 3a-2=54

Step-by-step explanation:

3 x her age - the 2 year will equal 54

6 0
3 years ago
Given f(x) = x^2 + x − 2 and g(x) = 2x − 4, identify (f + g)(x).
shutvik [7]

Answer:

(f + g)(x) = x^2 + 3x - 6

Step-by-step explanation:

Given f(x) = x^2 + x − 2 and g(x) = 2x − 4

Plug in:

(f + g)(x) = x^2 + x − 2 + 2x − 4

(f + g)(x) = x^2 + 3x - 6

3 0
2 years ago
Read 2 more answers
The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?
gladu [14]
We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub


p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
p= \frac {(x-6)(x+1)(x+4)}{(x-2)}

7 0
3 years ago
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