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ivann1987 [24]
3 years ago
12

Find the product (x-y) (8x+y)

Mathematics
1 answer:
Schach [20]3 years ago
8 0
89+6 
x - y 
^ - ^
3 - 9 I think that's the answer I'm not too sure because you didn't provide me your answer but hope this helps .

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Which phrase best describes f(x), graphed on the coordinate plane below? On a coordinate plane, a curve goes through two cycles.
igomit [66]

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5.6

Step-by-step explanation:

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Help pretty pretty please !!❤️
insens350 [35]

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The answer must be that it has a MAX

Step-by-step explanation:

Its because the graph has a MAXIMUM "peak" of the line--the maximum point on the graph of which it reaches!

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4 0
3 years ago
Fill in the blanks to rewrite the following statement with variables: Given any positive real number, there is a positive real n
sveticcg [70]

Answer:

a) there is s such that <u>r>s</u> and s is <u>positive</u>

b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r

Step-by-step explanation:

a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.

b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.

3 0
3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
4 years ago
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