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Marina CMI [18]
3 years ago
9

Simplify: 3/5x + x Where 3 over 5 x plus x

Mathematics
2 answers:
dexar [7]3 years ago
5 0

Answer:

\dfrac{8x}{5}

Step-by-step explanation:

Given that,

\dfrac{3}{5}x+x

In the given expression simplify the two terms

First we make the conman denominator of both term

denominator of first term is 5 and second term is 1.

We find the least common denominator of 5 and 1

That is 5

Multiply by 5 at numerator and denominator with second term

\Rightarrow \dfrac{3x}{5}+\dfrac{5x}{5}

write as common denominator, 5

\Rightarrow \dfrac{3x+5x}{5}

Combine the numerator, 3x+5x

\Rightarrow \dfrac{8x}{5}

Hence, The simplified form will be \dfrac{8x}{5}

hoa [83]3 years ago
4 0
3/(5x) + x = 3/(5x) + x/1 * (5x)/(5x)
= 3/(5x) + 5x²/5x
= (3+5x²) / 5x
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Answer:

<em>1+√3</em>

Step-by-step explanation:

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tan 45 = 4/AD

AD = 4/tan45

AD = 4/1

AD = 4

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DC = 4/(1/√3)

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6 0
3 years ago
Ayush and sumit take two different routes to school. Ayush's route is 1km 2hm long while sumit route is 2hm 30dam long while rou
emmasim [6.3K]

Answer:

Ayush's route is 0.7 km or 700m longer than Sumit route.

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Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.

We know that,

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Using these conversions we get

Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm

Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm

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Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.

4 0
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