Need help on Part A!
2 answers:
In part A, you have been tasked with constructing an algebraic expression that represents the total cost of kitten supplies.
There are two types of kittens identified in the question: young kittens and older kittens. Let's say m is the number of young kittens and n is the number of older kittens.
The young kittens' food is $3.99 per bottle. The older kittens' food is $1.50 per can.
Based on the number of each type of kitten, the cost will vary.
The second part of the question asks you to identify specific parts of the equation. The coefficients are 3.99 and 1.50. There are no constants in the expression. The variables are m and n.
Let k represent the cost of supplies, b the number of bottles, and c the number of cans. You know that the total cost is found by adding the number of bottles multiplied by the price of each to the number of cans multiplied by their unit price. (This is the computation performed anytime you purchase something.)
There are no constants in this equation.
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Answer:
The probability that the mean life expectancy of the sample is less than X years is the p-value of , in which
is the mean life expectancy,
is the standard deviation and n is the size of the sample.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
We have:
Mean , standard deviation
.
Sample of size n:
This means that the z-score is now, by the Central Limit Theorem:
Find the probability that the mean life expectancy will be less than years.
The probability that the mean life expectancy of the sample is less than X years is the p-value of , in which
is the mean life expectancy,
is the standard deviation and n is the size of the sample.