Need help on Part A!
2 answers:
In part A, you have been tasked with constructing an algebraic expression that represents the total cost of kitten supplies.
There are two types of kittens identified in the question: young kittens and older kittens. Let's say m is the number of young kittens and n is the number of older kittens.
The young kittens' food is $3.99 per bottle. The older kittens' food is $1.50 per can.
Based on the number of each type of kitten, the cost will vary.
The second part of the question asks you to identify specific parts of the equation. The coefficients are 3.99 and 1.50. There are no constants in the expression. The variables are m and n.
Let k represent the cost of supplies, b the number of bottles, and c the number of cans. You know that the total cost is found by adding the number of bottles multiplied by the price of each to the number of cans multiplied by their unit price. (This is the computation performed anytime you purchase something.)
There are no constants in this equation.
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Answer:
The required inequality is: 12 ≤ 3x < 21
Step-by-step explanation:
We are given: three times a number is greater than or equal to 12 and less than 21
We need to answer following questions:
1) The inequality translated in numerical form
Let number = x
12 ≤ 3x < 21
2) Your work solving the inequality
We need to find value of x. Divide the inequality by x
4 ≤ x < 7
3) The solution graphed on a number line
It is shown in figure attached.
4) The solution in set notation
The set notation is: Considering x belongs to natural numbers N
{∀ x|x∈N, 4 ≤ x < 7}
5) The solution in interval notation
The interval notation is: [4,7)
because we have 4 less than equal to x and x is less than 7
