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EleoNora [17]
3 years ago
5

A quality control inspector finds 9 defective units in a sample of 60 cellular phone. At this ratio, how many units can the insp

ector expect to find in a batch of 3000 such phones?
Mathematics
1 answer:
scoray [572]3 years ago
5 0

The inspector can expect to find 450 units in a batch of 3000 phones

Step-by-step explanation:

Given

Total Cellular Phones = S = 60

Defective phones = E = 9

We will calculate the probability of defective forms first

So,

P(d)=\frac{E}{S}\\=\frac{9}{60}\\=0.15

The probability of defective phones in 60 phones is 0.15

Now,

Total phones = 3000

P(d)=0.15*3000\\=450

The inspector can expect to find 450 units in a batch of 3000 phones

Keywords: Probability, Experimental probability

Learn more about probability at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

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A door alarm works in 72 out of 100 cases and surveillance camera works in 68 out of 100 cases. what is the probability of effec
Rudiy27

A door alarm works in 72 out of 100 cases.

surveillance camera works in 68 out of 100 cases.

The probability that method A is used = 72/100

The probability that method B is used = 68/100

Since both method are used we find the probability of A and B

Probability ( A and B) = \frac{72}{100} * \frac{68}{100}

= \frac{306}{625}

7 0
3 years ago
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Anesh normally buys 1.5 litre bottles of soft drink. At the supermarket he notices a promotion bottle that has 25 percent extra.
slavikrds [6]

Answer:

6ml

Step-by-step explanation:

=25%÷100%

=0•25

1.5l to ml

1L=1000ml

=1.5000ml÷0.25

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3 years ago
HELPP MEEE<br> BC I DIDNT POST MY PICCC
leonid [27]
It’s b , i hope it’s not wrong :)
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2 years ago
Plsss help no one answered the other times I put this question
svetlana [45]

Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

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Aleksandr-060686 [28]
C.4/11 is the answer to your question
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