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Delicious77 [7]
3 years ago
8

Which is equivalent to 64^1/4 ?

Mathematics
1 answer:
solong [7]3 years ago
3 0
64^{ \frac{1}{4} }=(2^6)^{ \frac{1}{4} }=2^{ \frac{6}{4} }=2^{ \frac{3}{2} }= \sqrt{2^3}=2 \sqrt{2}

I hope this helps.
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The ______ is the best measure of central tendency when there are extreme values in the distribution.
notka56 [123]
I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
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Select the correct translation for the following function:<br><br> g(x) = f(x + 8)
Blababa [14]

Answer:

This moves f(x) 8 units to the left

Step-by-step explanation:

g(x) = f(x + 8)

y = f(x + C) C > 0 moves it left

This moves f(x) 8 units to the left

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The perimeter of the rectangle below is 112 units. Find the length of side VW . Write your answer without variables. Top YX: 4z
dimaraw [331]

Answer:

VW = 33

Step-by-step explanation:

<em>See attachment for complete question</em>

Given

VY = 4x - 1

VW = 5x + 3

Perimeter = 112

Required

Determine the length of VW

Perimeter is calculated as:

Perimeter = 2 * (Width + Length)

This gives:

Perimeter = 2 * (VW + VY)

Substitute values for VW, VY and Perimeter

112 =  2 * (4x - 1 + 5x + 3)

Collect Like Terms

112 = 2 * (4x + 5x -1 +3)

112 = 2 * (9x +2)

Divide through by 2

56 = 9x + 2

Collect Like Terms

9x = 56 - 2

9x = 54

x = 54/9

x = 6

Substitute 6 for x in VW = 5x + 3

VW = 5 * 6 + 3

VW = 30 + 3

VW = 33

4 0
3 years ago
Simplify the following ratios:
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3 years ago
The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.
malfutka [58]

The number of pencils sold on the first day  is 5 pencils.

The number of notebooks sold on the first day  is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day   35 notebooks.

<u>Step-by-step explanation:</u>

Given data,

  • The total number of notebooks in the store = 45 notebooks.
  • The total number of Pencils in the store = 15 pencils.
  • The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

<u>In the first day :</u>

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day  = x

And,  the number of notebooks sold on the first day  = 2x (Twice as pencils).

<u>In the second day :</u>

The number of sale of notebooks and pencils are given by,

For every 7 notebooks​ sold, 2 pencils were sold.

The number of pencils sold on the second day =   2y

The number of notebooks sold on the second day   = 7y

<u> The equation is framed for number of notebooks sold on each day :</u>

The number of notebooks sold ⇒ 2x + 7y = 45   -------(1)

<u> The equation  is framed for number of pencils sold on each day :</u>

The number of pencils sold: x + 2y = 15  ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

  2x + 7y = 45

-<u> (2x + 4y) = 30</u>

   <u>        3y = 15  </u>

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day  = x ⇒ 5 pencils

The number of notebooks sold on the first day  = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day =   2y ⇒ 10 pencils

The number of notebooks sold on the second day   = 7y ⇒ 35 notebooks.

8 0
3 years ago
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