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bixtya [17]
3 years ago
12

Help please guys thanks

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

False

Step-by-step explanation:

a^(m/n)=sqrt_{n}a^m

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-(-E)=0.6 , I am not sure of my answer

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6.025 (25 is repeating) as a mixed number
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6.025 as a mixed number is 6 1/40

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3 years ago
URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cot
Naddika [18.5K]

The student that simplified the expression incorrectly is student 2

<h3>How to determine the incorrect result?</h3>

The steps are given as:

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}

Student 1:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: 1 + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 3: 1 + tan²(Ф)
  • Step 4: sec²(Ф)

Student 2:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}
  • Step 3: sec²(Ф)/tan²(Ф)
  • Step 4: csc²(Ф)

As a general trigonometry rule;

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

Read more about trigonometric expressions at:

brainly.com/question/8120556

#SPJ1

5 0
2 years ago
Plzzzzzzzzzzaaaaaaaaa
TEA [102]

Answer:

8 and 9

Step-by-step explanation:

I got it online wimpy moderators! so there is no work  as I said  before

5 0
3 years ago
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