Answer:
The answer is 0.9726
Step-by-step explanation:
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
To learn more on quadratic equations: brainly.com/question/17177510
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Answer: ∠ABE=20°
Step-by-step explanation:
∵ AB=BC
∴ ΔABC is a isosceles triangle
∵ ∠A=30
∴ ∠C=30
∵ The interior angle sum of triangle is 180°
∵ ∠A+∠B+∠C=180
30+∠B+30=180
∠B+60=180
∠B=120 (∠ABC)
∵ ∠EBD+∠ABE+∠ABC=linear pair
∴∠EBD+∠ABE+∠ABC=180°
4x+2x+120=180
6x+120=180
6x=60
x=10
∠ABE=2x=2(10)=20°
Hope this helps!! :)
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