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jeyben [28]
3 years ago
13

There are 6 students participating in a poetry contest, in how many ways can the students who go first and second in the bee be

chosen?
Mathematics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

There are are 30 possible ways for the 6 students to be ranked 1st and 2nd

Step-by-step explanation:

There are 6 students, and any of them could receive first place. Therefore, there are 6 possibilities for first place.

A student cannot receive first and second place, so the student who won first place cannot also win second place. Therefore, there are only 5 students who could win second place.

We can multiply these two possibilities to find the number of possible rankings of 1st and 2nd

6*5=30

There are are 30 possible ways for the 6 students to be ranked 1st and 2nd....

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tangare [24]

Answer:26x will be your answer

8 0
3 years ago
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1. 5/2=-x/11<br><br> 2. 9/m=-4/11
alex41 [277]

Answer:

1. x = 55/2

2. x = - 99/4

5 0
3 years ago
What would the answer be because I already tried everything and I just can’t get it
Mrac [35]

Answer:

e = 56

Step-by-step explanation:

Use cross multiplication.

28 * 14 = 7e

Simplify

392 = 7e

Divide each side by 7

e = 56.

5 0
3 years ago
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A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
-x+ 2y = 10<br> -3x+By = 11
adoni [48]

Answer:

change the equation into one variable.

2 y equals 10 + x

y equals 5 + x by 2

now put that into the second equation

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-3x+b(5+ x/2)

-3x + b5 + bx/2 = 11

8 0
3 years ago
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