A group of 7 people want to equally share 33 1/4 ounces of cake. How much will one person get
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Hello there.
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
+ 
=
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span> + = 
.
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span>
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>
CE ⊥ CF because m∠ECA + m∠FCA = 90°
Step-by-step explanation:
In ∆ABC
- On the extension of the side BC , draw a line segment CD ≅ CA
- Draw the segment AD
- The line segment CE is the angle bisector of ∠ACB
- The line segment CF is the median towards AD in ∆ ACD
We want to prove that CF ⊥ CE
Look to the attached figure
In Δ ABC
∵ CE is the bisector of angle ACB
∴ ∠ACE ≅ ∠BCE
In Δ ACD
∵ CA = CD
∴ Δ ACD is an isosceles triangle
∵ AD is the median towards AD
- In any isosceles triangle the median from a vertex to its opposite
side bisects this vertex
∴ AD bisects ∠ACD
∴ ∠ACF ≅ ∠DCF
∵ BCD is a straight segment
∵ CE , CA , CF are drawn from point C
∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°
∵ m∠ACE ≅ m∠BCE
∵ m∠ACF ≅ m∠DCF
- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF
∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°
∴ 2 m∠ACE + 2 m∠ACF = 180°
- Divide all terms by 2
∴ m∠ACE + m∠ACF = 90°
∴ EC ⊥ CF
CE ⊥ CF because m∠ECA + m∠FCA = 90°
Learn more:
You can learn more about perpendicular lines in brainly.com/question/11223427
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