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3 years ago

Help please ill give 12 points for the right answer

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

It’s it four I think hope it helps

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Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

6 0

3 years ago

HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <333

alekssr [168]

Answer:

$\bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}$

Step-by-step explanation:

$-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7$

4 0

3 years ago

4. (03.06 MC)

bazaltina [42]

Step-by-step explanation:

Volume of a cylinder is:

V = πr²h

V = (3.14) (4 in)² (5 in)

V = 251.2 in³

Volume of a cone is:

V = ⅓ πr²h

V = ⅓ (3.14) (4 in)² (15 in)

V = 251.2 in³

The volumes are equal.

8 0

3 years ago

HELP ME HELP ME <br><br> What is the slope of the line?

satela [25.4K]

I think it is - 1/2
Or it could be 1/2 I am not that sure
Someone correct me if I am wrong
But I think it is - 1/2

3 0

3 years ago

) Solve this equation: − 10 + = 8 + 2 − 18

nikitadnepr [17]

Answer:

I think the question is wrong check ur question and I will answer

4 0

2 years ago