It’s obviously -2 because you can’t do 2 positives (2) and (2) to get another positive your going to get a negative so the correct answer is -2
Answer:
the price before taxes was $18,229.13
Step-by-step explanation:
Answer:
a. 205320
b. 34220
c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
Step-by-step explanation:
a) The number of ways to dustribute exams among the TA's is:
n / (n - r)!
n= number of things to choose from
r= Choosing r number
60P3= 60! / (60 - 3)!
(60)(59)(58)(57)! / (57)!
=205320
B) The number of ways to dustribute the exams among the TA's is:
n! /(n - r)! r!
60C3= 60! /(60 - 3)! 3!
= 60!/ 57! 3!
= 60 × 59 × 58 / 3 × 2 × 1
= 34220
C) The required number of ways is:
60C25 + 60C20 + 60C15
= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
Question 14:
We are given that:
C = πd
To solve for d, we need to isolate the d on one side of the equation. This means that we need to get rid of the π next to the d.
In order to do so, we can simply divide both sides of the equation by π as follows:
C/π = πd/π
d = C/π .........> The first option
Question (15):
We are given that:
d = rt
To solve for r, we need to isolate the r on one side of the equation. This means that we need to get rid of the t next to the r.
In order to do so, we can simply divide both sides of the equation by t as follows:
d/t = rt/t
r = d/t.........> The third option
Hope this helps :)
Hello,
Part A:
f(2)=4*2²=16
f(1)=4*2^1=8
2-1=1
(f(2)-f(1))/(2-1)=(16-8)/1=8 ; r_1=8
f(3)=4*2^3=32
f(4)=4*2^4=64
(f(4)-f(3))/(4-3)=(64-32)/1=32 ; r_2=32
Part B:
r_2=32=4*8=4*r_1
Explainations:
(4*2^2-4*2^1)/(2-1)=4*2^1(2-1)=4*2
(4*2^4-4*2^3)/(4-3)=4*2^3*(2-1)=4*8=(4*2)*4
