6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer:
vertex (5,2)
axis of symmetry: x=5
Step-by-step explanation:
vertex (h,k)
y = a(x - h)² + k
f(x)=(x-5)²+2 a = 1 h = 5 k = 2
vertex (5 , 2)
The axis of symmetry always passes through the vertex of the parabola. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
x = 5
The answer is
<span>A. 2/14, 3/21, 4/28
B. 1/8, 2/16, 3/24
C. 1/9, 2/18, 3/27
D. 5/40, 5/45, 5/50</span>