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denpristay [2]
3 years ago
10

Two opposite rays____form a line. A. Always B. Never C. Sometimes

Mathematics
1 answer:
Sati [7]3 years ago
6 0

A. Always. Good luck!!!!

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An element with mass 780 grams decays by 16.3% per minute. How much of the element is remaining after 16 minutes, to the nearest
vitfil [10]
Exponential decay is a very common process especially when we are talking about radioactive materials. So, there is already a common formula for this type of behavior which is written below:

A = Pe^-rt
where
A is the amount left after time t
P is the initial amount at t=0
r is the rate

Substituting the values,
A = (780 g)(e^-0.163*16)
A = 57.5 g
8 0
4 years ago
Solve when m = 7 and k = 2<br><br> 6m- 3k<br><br> A.30<br> B.21<br> C.36<br> D.35
NARA [144]
Agree with the one at the top it’s 36
6 0
3 years ago
Read 2 more answers
Aquestion that can be answered by<br> collecting data that has variability,
riadik2000 [5.3K]

You need to give more info

8 0
3 years ago
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
If a line of one billion people stretched 327,495 miles long, the average shoulder width of the people in the line is A feet. Ro
Ganezh [65]

Answer:

  1.7 ft

Step-by-step explanation:

We presume you want to find A. And we presume the people are standing shoulder-to-shoulder.

  (327,495 mi)/(10^9 persons) = (3.27495×10^5 mi)/(10^9 persons) × (5280 ft/mi)

  = 1.7291736×10^9 ft/(10^9 persons)

  = 1.7292736 ft/person

  ≈ 1.7 ft/person

3 0
3 years ago
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