The interval of filled bags is at confidence interval of 95%.
At 95% confidence interval, Z=1.96 (from Z tables).
But,
Z= (x-mean)/sd => 1.96 = (x-450)/20 => x (upper limit)= 20*1.96+450489 bags
Lower limit or minimum number bags to avoid replace= 450-1.96*20 =411 bags
Answer:
8 days.
Step-by-step explanation:
There are 15 people after the 3 have joined so by proportion the number of days that the supplies will last is 12/15 ( = 4/5) of the ten days.
= 4*10 / 5
= 8 days.
A=16500(1-0.0575)^5
A=16,500×(1−0.0575)^(5)
A=12,271.30
Answer:
1/2
Step-by-step explanation:
2/4 is equal to 1/2, because if you divide 4 by 2 you get 2, and if you divide 2 by 2 you get one.
Basically, the simplification process would look something like this...
2/4 ÷ 2/2 = 1/2
