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3 years ago

Why can you use a model to check your answer for a division problem

Mathematics

1 answer:

dangina [55]3 years ago

8 0

Because if you a model your not going to get the right answer

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Help ASAP.

denpristay [2]

$1.\\A(n)=-2\cdot5^{n-1}\\\\\text{Find the first, fourth, and eighth terms}\\\text{It means}\ A(1),\ A(4)\ \text{and}\ A(8).\\\\\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{in}\ A(n):\\\\A(1)=-2\cdot5^{1-1}=-2\cdot5^0=-2\cdot1=-2\\\\A(4)=-2\cdot5^{4-1}=-2\cdot5^3=-2\cdot125=-250\\\\A(8)=-2\cdot5^{8-1}=-2\cdot5^7=-2\cdot78,125=-156,250\\\\\boxed{Answer:\ a)\ -2,\ -250,\ -156,250}.$

$2.\\a_1=-6,\ r=2\\\\\text{The formula of a n-th term of geometric sequence}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=-6\cdot2^{n-1}=-6\cdot2^n\cdot2^{-1}=-6\cdot2^n\cdot\dfrac{1}{2}=-3\cdot2^n\\\\\boxed{Answer:\ A(n)=a_n=-3\cdot2^n}$

4 0

3 years ago

Find the common ratio of the geometric sequence 1.5, 4.5, 13.5, 40.5, …

Viktor [21]

Answer:

The common ratio is 3.

Step-by-step explanation:

Take 4.5 and divide it by 1.5 and you find that the common ratio is 3. To ensure this is the answer you can multiple 4.5 by 3 and you'll get 13.5

6 0

3 years ago

Which is the ratio of the number of months that begin with the letter J to the total number of months in a year? (2 points) 12 t

jeka57 [31]

Answer:

3-12

Step-by-step explanation:

January

June

July

That is 3 months out of 12 so...3 to 12

8 0

4 years ago

Express the prime number 31 in the form 2^p − 1 where p is a prime number and as a difference of two perfect squares using the i

stellarik [79]

Answer:

31 = 2⁵ -1

31 = 16²- 15²

Step-by-step explanation:

As we know that

2¹=2

2²= 4

2³= 8

2⁴= 16

2⁵=32

32 = 2⁵

By subtracting 1 in bot sides

32-1 = 2⁵ -1

31 = 2⁵ -1

2⁵ -1 = 31

By comparing with

$2^p-1$

p= 5

As we know that

15²= 225

16² = 256

16²- 15² = 256-225 = 31

16²- 15² = (16+15)(16-15)

31 = (16+15)(16-15)

5 0

4 years ago

Anna is planning a big birthday bash for her sixteenth birthday party and wants to invite as many people as possible but she has

Doss [256]

Im not an expert or anything, but i think for the innequality, i would say

$6.50p + 100 \leqslant 500$

as far as the amount of people she can invite, do 500-100=400 because of the setup fee, then, to find how many people she can invite. 400÷6.50 which leaves you with the highest amount of people she can invite without going over budget, as 61.

3 0

4 years ago