
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
Answer:
I think it is 84 hope this helps
I believe these are the answers.
A
i) (y=5) x=6
ii) (y = -1) x=0
iii) (y = -2) x = -1
B
i) (x = -4) y = -5
ii) (x=2) y=1
iii) (x=5) y=4
Sorry if these are wrong but I hope the help.
If in 2000 there were 430 folksk, 2010 is 10 years later, thus t = 10