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FromTheMoon [43]
3 years ago
14

Henry steps onto an elevator at the first floor. He goes up to the 9th floor and then comes down 2 floors. He then goes up 4 flo

ors and down 6 floors. What floor is Henry on? A. 2 B. 3 C. 4 D. 5
Mathematics
2 answers:
Anika [276]3 years ago
5 0

Answer:

I think it is c but I am not sure but u can try asking a tutor

Ahat [919]3 years ago
5 0

Answer:

dude above  wrong its b

Step-by-step explanation:

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What is the area of this figure?
andrew11 [14]
I believe that’s angle
5 0
4 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
Please help ;((( I'm stuck
Setler79 [48]

Answer:

I think it is 84 hope this helps

8 0
3 years ago
Please help me!! I'm not good at math ✌
Bezzdna [24]
I believe these are the answers.
A
i) (y=5) x=6
ii) (y = -1) x=0
iii) (y = -2) x = -1
B
i) (x = -4) y = -5
ii) (x=2) y=1
iii) (x=5) y=4
Sorry if these are wrong but I hope the help.

6 0
3 years ago
The population of a town in 2000 was 430. The population is increasing at a rate of 0.9% every year. What will be the projected
Naddik [55]
If in 2000 there were 430 folksk, 2010 is 10 years later, thus t = 10

\bf \qquad \textit{Amount for Exponential Growth}\\\\&#10;A=I(1 + r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &430\\&#10;r=rate\to 0.9\%\to \frac{0.9}{100}\to &0.009\\&#10;t=\textit{elapsed time}\to &10\\&#10;\end{cases}&#10;\\\\\\&#10;A=430(1+0.009)^{10}\implies A=430(1.009)^{10}
7 0
4 years ago
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