Z=22
180-120=60
2x+16=60
2x=44
Z=22
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
1577.8 US dollars are received for 1127 UK pounds.
5669.5 UK pounds are received for US$7937.3.
Step-by-step explanation:
The questions are solved by proportions, using a rule of three.
How many US dollars are received for 1127 UK pounds?
1 UK pound = 1.4 US dollars
1127 UK pounds - x US dollars
Applying cross multiplication:

1577.8 US dollars are received for 1127 UK pounds.
How many UK pounds are received for US$7937.3?
1 UK pound = 1.4 US dollars
x UK pounds - 7937.3 US dollars



5669.5 UK pounds are received for US$7937.3.
The acceptable first step in simplifying the expression
is (a) 
The expression is given as:

To change the form of the expression, we simply perform several arithmetic operations on it.
Start by multiplying the expression by 1/1

Express 1 /1 as (1 - sec x)/(1 - sec x)

Rewrite the above expression as follows:

Hence, the acceptable first step is (a)
Read more about trigonometry ratios at:
brainly.com/question/24888715
Answer:
you can buy 4 bags of grapes with $12.
Step-by-step explanation:
Hope this helps :)