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snow_lady [41]
3 years ago
15

Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6)

Mathematics
1 answer:
igomit [66]3 years ago
8 0
f(x)=ax^2+bx+c\\\\(0;\ 3)\to x=0;\ y=3\to f(0)=3\\therefore\\3=a\cdot0^2+b\cdot0+c\\\boxed{c=3}\\\\(1;\ 4)\to x=1;\ y=4\to f(1)=4\\therefore\\4=1^2\cdot a+1\cdot b+3\\4=a+b+3\ \ \ |subtract\ 3\ from\ both\ sides\\(1)\boxed{a+b=1}\\\\(-1;-6)\to x=-1;\ y=-6\to f(-1)=-6\\therefore\\-6=(-1)^2a+(-1)b+3\\-6=a-b+3\ \ \ \ |subtract\ 3\ from\ both\ sides\\(2)\boxed{a-b=-9}

We have (1) & (2):

\underline{+\left\{\begin{array}{ccc}a+b=1\\a-b=-9\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ 2a=-8\ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \boxed{a=-4}\\\\subtitute\ the\ value\ of\ "a"\ to\ the\ first\ equation\\\\-4+b=1\ \ \ \ |add\ 4\ to\ both\ sides\\\boxed{b=5}\\\\Answer{\boxed{\boxed{f(x)=-4x^2+5x+3}}
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It costs $3.45 to buy 3/4 lb of chopped walnuts. How much would it cost to purchase 12 lbs of walnuts? Enter the numeric value o
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Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write
Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

  • Use double point formula and simplify it to get two eqaution.
  • Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

~ Keep all values.

(y  + 4) =  \frac{11 + 4}{2 + 1} (x + 1)

~ Simplify it.

y + 4 =  \frac{15}{3} (x + 1)

y + 4 = 5x + 5

5x - y + 1 = 0

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1}(x - x1)

~ Keep all values.

(y - 1) =  \frac{10 - 1}{4 - 1} (x - 1)

~ Simplify it.

y - 1 = 3 x - 3

3x - y - 2 = 0

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

m1 =  \frac{ - coeff. \: of \: x}{coeff \: of \: y}

m1 =  \frac{ - 5}{ - 1}

Therefore, m1 = 5

Slope of second equation.

m2 =  \frac{ - coeff \: .of \: x}{coeff \: .of \: y}

m2 =   \frac{ - 3}{ - 1}

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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