1 người khởi hành từ A lúc 7 giờ sáng và dự định tới B lúc 11 giờ 30 phút cùng ngày. Do đường chưa tốt, nên người ấy đã đi với v
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The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
The rational roots of the polynomial given in the question are -4/5 and 3/4.
Given-
Given polynomial function is,
The given polynomial function has the four-degree equation in which the greatest power of the variable is four. Suppose one root of <em>x </em>is 1 to solve it further. So one factor is,
Rewrite the given equation,
On the factor above equation, we get.
On the factor, we get,
Hence, the rational roots of the polynomial given in the question are -4/5 and 3/4.
For more about the polynomial, follow the link below-