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lisabon 2012 [21]

3 years ago

15

the equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two complex solutions d. no solution

2 answers:

TEA [102]3 years ago

6 0

(x+7)(x-1) = -16

x² + 6x - 7 = -16

x² + 6x - 7 + 16 = 0

x² + 6x + 9 = 0

(x+3)² = 0

x = - 3 -> one real solution

Anni [7]3 years ago

5 0

Here’s my answer! Hope it makes sense :)

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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...

katovenus [111]

Answer:

$a_{12}=-244140625$

Step-by-step explanation:

Considering the geometric sequence

$5,-25,\:125,\:...$

$a_1=5$

As the common ratio ' $r$ ' between consecutive terms is constant.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$r=\frac{-25}{5}=-5$

$r=\frac{125}{-25}=-5$

The general term of a geometric sequence is given by the formula:

$a_n=a_1\cdot \:r^{n-1}$

where $a_1$ is the initial term and $r$ the common ratio.

Putting $n = 12$ , $r = -5$ and $a_1=5$ in the general term of a geometric sequence to determine the 12th term of the sequence.

$a_n=a_1\cdot \:r^{n-1}$

$a_n=5\left(-5\right)^{n-1}$

$a_{12}=5\left(-5\right)^{12-1}$

$=5\left(-5^{11}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-5\cdot \:5^{11}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=-5^{1+11}$ ∵ $5\cdot \:5^{11}=\:5^{1+11}$

$=-244140625$

Therefore,

$a_{12}=-244140625$

6 0

3 years ago

Can u please help me with this u know who u are

Dahasolnce [82]

4/7s+6/7 is the answer

4 0

3 years ago

Help plz will give brainliest

jolli1 [7]

Answer: 5(13.5-4.5)

5(9)

=45

6 0

3 years ago

How do I simplify 5 3/2

Volgvan

Note the improper fraction. Change it into a mixed fraction

3/2 = 2/2 + 1/2

2/2 = 1

5 + 1 1/2

Simplify.

5 + 1 = 6

6 1/2 is your answer

hope this helps

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3 years ago

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Find the surface area of a cube that is 5/8

vlabodo [156]

Answer:

A=6a2

Step-by-step explanation:

8 0

3 years ago

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