Question

the equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two complex solutions d. no solution

Answer 1

(x+7)(x-1) = -16

x² + 6x - 7 = -16

x² + 6x - 7 + 16 = 0

x² + 6x + 9 = 0

(x+3)² = 0

x = - 3 -> one real solution

Answer 2

Here’s my answer! Hope it makes sense :)