Question

Solve the system of equations given below.

Answer 1

Answer:

Step-by-step explanation:

we have the system :

8x+4y=16

7y=15

the easiest unknown to find first is y because we have the second equation contains only y :

7y=15   we divide both sides by 7 we get : y=$\frac{15}{7}$

then we can substitute this value in the first equation to find x :

8x+4 $\frac{15}{7}$ = 16

means : 8x+$\frac{60}{7}$ = 16

8x=16-$\frac{60}{7}$

8x = $\frac{52}{7}$

divide both sides by 8 :

x = $\frac{13}{14}$

so the solution is ($\frac{13}{14}$,$\frac{15}{7}$)

this is the solution of the system you submitted

Now if you meant this system :

8x+4y=16

7y=15-1    

we get :

7y=14   which gives us y=2

then 8x+4(2)=16   gives us : 8x+8=16

means 8x=8  

means x=1

and in this case the solution will be (1,2)  answer C

Answer 2

Answer:

x = \frac{13}{14}

Step-by-step explanation:

8x+4y=16

7y=15

the easiest unknown to find first is y because we have the second equation contains only y :

7y=15   we divide both sides by 7 we get : y=\frac{15}{7}

then we can substitute this value in the first equation to find x :

8x+4 \frac{15}{7} = 16

means : 8x+\frac{60}{7} = 16

8x=16-\frac{60}{7}

8x = \frac{52}{7}

divide both sides by 8 :

x = \frac{13}{14}

so the solution is (\frac{13}{14},\frac{15}{7})