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andrezito [222]
3 years ago
12

A researcher observes and records the height of a weight moving up and down on the end of a spring. At the beginning of the obse

rvation the weight was at its highest point. From its resting position, it takes 20 seconds for the weight to reach its highest position, fall to its lowest position, and return to its resting position. The difference between the lowest and the highest points is 6 in. Assume the resting position is at y = 0.
Mathematics
1 answer:
andreev551 [17]3 years ago
8 0

i have a easy way but u cant do it it needed 2 pages

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3. If the sum of (3+6i) and (4+pi) is (7+81), then what is the value of p?
Aliun [14]

Answer:

p=2

Step-by-step explanation:

(3+6i) and (4+pi) is (7+8i)

3+4 = 7

6i+pi = 8i

Subtract 6i from each side

pi = 8i-6i

pi = 2i

That means p = 2

8 0
3 years ago
It's to hard and I can't figure it out
maria [59]

Answer:

The triangles are the same though, what do i do?

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A person x inches tall has a pulse rate of y beats per​ minute, as given approximately by yequals600 x Superscript negative 1 di
tankabanditka [31]

Answer:

a) 5.13beats/min

b) 2.82 beats/min

Step-by-step explanation:

Given the pulse rate of a person modelled by the equation y = 600x^-1/3 for 30≤x≤75

If the height is 39inches, the instantaneous rate of change of pulse rate for the heights will be expressed as;

y = 600(39)^-1/3

y = {600(1/39)}/3

y = 600/39×3

y = 600/117

y ≈ 5.13beats/min

The instantaneous rate for a 39 inches tall person is 5.13 beats per min

b) For a 71inches tall person, the beat rate will be expressed as;

y = 600(71)^-1/3

y = {600(1/71)}/3

y = 600/71×3

y = 600/213

y ≈ 2.82 beats per minute

The instantaneous rate for a 71 inches tall person is 2.82 beats per min

7 0
3 years ago
Evaluate this exponential expression 7 • (6+2)^2 - 3^2=
Lelu [443]

Answer: 441

Step-by-step explanation:

7*(6+2)^2-3^2

7*8^2-3^2

7*64-9

448-9

441

3 0
2 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
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