Answer:
<em>Number of story books bought = 100
</em>
<em>
C.P. of each book = Rs. 135
</em>
<em>
C.P. of all 100 books = Rs. (135×100)= Rs. 13500
</em>
<em>
C.P. of 90 books = Rs. (135×90)= Rs. 12150
</em>
<em>
Number of books donated = 10
</em>
<em>
Number of books sold = 100-10=90
</em>
<em>
Loss% in the transaction = 2%
</em>
<em>
S.P. of all books = (C.P./100)(100-loss%)
</em>
<em> =Rs. (12150/100×98)
</em>
<em>
Thus, S.P. of each book
</em>
<em>
= Rs. {(12150/100×98)÷90}
</em>
<em>
= Rs. (12150/100×98/90)
</em>
<em>
= Rs. 132.3</em>
Answer:
the answer is 14/27
Step-by-step explanation:
Answer:
x squared plus two times x minus one = zero.
Step-by-step explanation:
(This is a Quadratic equation in the variable x).
Answer:
14 divide 5 =3.1 is your answer if I'm not wrong
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
