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Helga [31]
3 years ago
15

Ill give brainiest - please help ASAP with WORK FOR IT please and thank you!! :) 30 points

Mathematics
1 answer:
pentagon [3]3 years ago
6 0

Answer:

hope this helps .keep on learning

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Which transformations could have occurred to map triangle ABC triangle A^ * B^ n C^ prime
zloy xaker [14]

Reflection and dilation is the transformation which will occur to map triangle ABC triangle to A^ * B^ n C^ prime.

<h3>What is a Triangle?</h3>

This refers to a plane figure which has features such as three angles and three sides.

Reflection and dilation involves flipping and enlargement/reduction respectively which gives rise to the sides being changed.

Read more about Triangle here brainly.com/question/1058720

#SPJ1

3 0
2 years ago
What is the slope and equation of a line parallel to the x-axis passing through point (3,7)
Law Incorporation [45]
Thats when point =0. equation of a line mx +b where m is the slope
and b is the intercept
6 0
3 years ago
=) The perimeter of a rectangular field is 336 m.
goldenfox [79]

Answer:

Length of the field: 94 m

Width of the painting: 61 cm

Step-by-step explanation:

Use the perimeter formula, P = 2l + 2w, to find the length:

Plug in the perimeter and width into the equation:

P = 2l + 2w

336 = 2l + 2(74)

336 = 2l + 148

188 = 2l

94 = l

So, the length of the field is 94 m.

To find the width of the painting, use the area formula, A = lw

Plug in the area and length into the equation:

A = lw

5795 = 95w

61 = w

So, the width of the painting is 61 cm.

Length of the field: 94 m

Width of the painting: 61 cm

4 0
3 years ago
Explain the algebra 5a - 9a - (-2a) =
sleet_krkn [62]

Hello!

5a - 9a - (-2a) =

= 5a - 9a + 2a =

= -4a + 2a =

= -2a

Good luck! :)

7 0
3 years ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
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