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Goshia [24]
4 years ago
5

a box is a cuboid with dimensions 28cm by 15 cm by 20 cm all measured to the nearest centimetre. Disc cases are cuboids which me

asure 1.5 cm by 14.2 cm by 19.cm all measured to the nearest millimetre.Show that 17 disc cases, stacked as shown, will definitely fit in the box.
Mathematics
2 answers:
nataly862011 [7]4 years ago
7 0

Answer:

See Below

Step-by-step explanation:

To get volume of cuboid, we multiply the 3 dimensions.

<u>Volume of Box</u> = 28 * 15 * 20 = 8400

<u>Volume of 1 disc case</u> = 1.5 * 14.2 * 19 = 404.7

<u>Volume of 17 disc cases</u> = 17 * 404.7 = 6879.9

Since, volume of 17 disc cases is less than volume of the cuboid box, definitely 17 disc cases will fit the box.

chubhunter [2.5K]4 years ago
4 0

Answer:

This only got my 2 out of 4 marks but I hope it is still helpful and you can work on it.

Step-by-step explanation:

<u>27.5×14.5×19.5 </u>= 7775.625cm³

<u>1.55×14.25×19.35</u> = 427.393125cm³

7775.625÷427.393121 = 18.19314495

This is about upper and lower bound so anybody please carry on and help me here is a start the part underlined is where I got the marks

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4 years ago
I don’t know how to do it can someone help me?
frozen [14]

Answer:f(g(0))= 1/5

              g(f(0))= 7

Step-by-step explanation:

for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3

                                                                                                    =3

 so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2

                                     = 1/5

so f(g(0)) is equal to 1/5

Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2

                                                                                               =1/2

now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3

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                                                                         =7

so g(f(0)) is equal to 7

Hope this helps:)

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