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Luba_88 [7]
3 years ago
8

Alex is a high school sophomore who recently learned about the importance of

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
I don’t understand how to do this
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A $525 speaker now sells for $393.75. Find the percent of change.
antiseptic1488 [7]

Answer: 25%

Step-by-step explanation:

595 - 393.75 = 131.25

131.25 (amount of change)/ 525 (original amount) x 100%

= 25%

8 0
3 years ago
What is 3/4 = w + 2/5
shusha [124]
Convert all fractions to have the same denominator. 

To convert, we must find the least common multiple of the two denominators of the fractions:

Multiples of 4: {4,8,12,16,20}
Multiples of 5: {5,10,15,20}

The least common multiple of 4 and 5 is 20. 

Multiply the fractions by a number that will result in the denominator being 20:

\frac{3}{4} * \frac{5}{5} = \frac{15}{20}

\frac{2}{5} * \frac{4}{4} = \frac{8}{20}

The equation should now look like this:

\frac{15}{20} = w + \frac{8}{20}

Subtract both sides by 8/20 to get w by itself:

\frac{15}{20} - \frac{8}{20} = \frac{7}{20}

w = \frac{7}{20}

The value of w is 7/20.
7 0
3 years ago
Read 2 more answers
Raymond has taken a position as the navigator on a speed boat racing team. The team entered a race that starts at Daytona Beach,
Zolol [24]
Wow. ok, I didn't expect this to be a triangle question.
You would need to use cosine to solve this.
Side 1: 160<span>     opposite angle: </span>58°
<span>Side 2: </span>180<span>     opposite angle: </span>73°
<span>Side 3: </span>140<span>     opposite angle: </span><span>48°</span>
7 0
3 years ago
Read 2 more answers
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
The hypotenuse of a 45°-45°-90° triangle measures units.
Sholpan [36]
This an isosceles right triangle. The sides opposed to the angle 45° are congruent. Let x be this side==> x²+x² =(7√2)² (Pythagoras)

2x² = 49(2) ==> 2x²= 98  ==> x²=49 & x=7
5 0
3 years ago
Read 2 more answers
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