2 years ago

Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!

Mathematics

1 answer:

MArishka [77]2 years ago

7 0

Answer:

- 18y = 1

Step-by-step explanation:

Adding the 2 equations term by term on both sides gives

(- 5x + 5x) + (- 9y - 9y) = (3 - 2), that is

0 + (- 18y) = 1

- 18y = 1

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Klio2033 [76]

What are you asking?

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2 years ago

Answe these two, please show your work

I am Lyosha [343]

8+5x(-4)-(-6+-2)

13 x -4 - -6+-2

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2 years ago

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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms . The ball's height h (in meters) af

Alecsey [184]

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms

Balls height $h= 2 +9t -5t^2$

To find all values of t for which the ball's height is 3 meters

We plug in 3 for h and solve for t

$h= 2 +9t -5t^2$

$3 = 2 +9t -5t^2$

Solve for t

$0= -1+ 9t -5t^2$

$5t^2 - 9t + 1 = 0$

Solve using quadratic formula

$t= \frac{-b+- \sqrt{b^2-4ac} }{2a}$

$t= \frac{9+- \sqrt{(-9)^2-4*5*1} }{2*5}$

After simplifying this,

$t= \frac{9+\sqrt{61}}{10}$ = 0.11898

$t= \frac{9-\sqrt{61}}{10}$ = 1.68102

the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec

5 0

2 years ago

Plsss help, will reward brainliest!!! Thank you.<br><br><br><br> Look at picture^^^

Step2247 [10]

Answer:

-2b and -0.9b and b/12

Step-by-step explanation:

6 0

2 years ago

Find the unit rate: 6 and 2/5 rotations in 2 and 2/3 seconds.

GrogVix [38]

I'd suggest you write "6 2/5," not "6 and 2/5."

6 2/5 rotations
-------------------- =
2 2/3 seconds

32
---
5 32 3
------- = ------ * -----
8 5 8 Reduce that 32/8: obtain 4.
---
3

Then we have

4(3)/5, or 12/5 rotations per sec.

4 0

2 years ago