Answer:
3676.44 rad/min
Step-by-step explanation:
It is a problem about the angular speed of the car's wheel.
You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:
( 1 )
v: speed of the car = tangential speed of the wheels = 47mph
r: radius of the wheels = 27/2 in = 13.5 in
you change the units of the speed:
next, you replace the values of v and r in the equation (1):
Then, the car's tires are turning with an angular speed of 3676.44 rad/min
The trip there is 58.5$ and the trip back is 63$. 63-58.5= 4.50. Which makes the answer B
Answer:
Step-by-step explanation:
1)
O = center of circle (origin)
we know that the angle at the center of the circle ∠ ROS will be
180= 2(31) + ∠x
180-62 = ∠x
118° = ∠x
The supplemental angle to the 118° will be 62°
62° is the interior angle to arc QR , so
arc QR is also 62°
3)
b/c the intercepted arc YZ = 2* 68=136
then 136+125+? = 360
? = 99°
arc ZX = 99°
5)
O= center point
we are given the two arcs 120 and 70 for both of these we know that the
interior angles will be the same. ∠JOX has a central angle of 120 , then
b/c triangle JOX is an isosceles, we know that the two angles J and X of
the triangle JOX will be 1/2 of 60 , or 30 each
also for
also ∠XOY has an interior angle of 70 so the two angle at X and Y will be 1/2 of 110 , or 55°
now add 55+30 to find X for box XYZJ
85° = ∠X
Did you mean this? <span>3^2x+1=3^x+5 => 3^(2x+1) = 3^(x+5)? If so, then 2x+1 is necessarily equal to x+5, so that 2x+1=x+5. Thus, x = 4 (answer).
Those parentheses are not optional; they must be part of your problem statement and solution.</span>
