Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
There would be 19.2 cups. At least from what I am thinking of. So you would get 19 cups and about a fourth of another cup. I hope this helps! :)
(b)(b)=25 cm2
b2=25 cm2
√(b2)=√(25 cm2)
b= 5 cm
Please note the square root of 25 was taken, as well as the square root of cm2.
Perimeter=4b
Perimeter=4(5 cm)
Perimeter=20 cm
Step:
A circle of radius = 12.5 or diameter = 25 or circumference = 78.54 cm has an area of: 4.909 × 10-8 square kilometers (km²) 0.04909 square meters (m²)
Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC = 
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² =
+ x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
V=LWH
h=10
V=360
360=LW10
divide both sides by 10
36=LW
try some values
ok so if we get L=1 and W=36, that is the same box as L=36 and W=1
so
L,W
36,1
18,2
12,3
9,4
6,6
5 of them
answer is 5 different boxes
dunno what the 'compare volume' is