For the function f(x)=x^2-5x+6, where is the y-intercept?

Find the length indicated. ? 5 5) G 17 A) 12 B) 36 C) 21

Crank

Answer:

your answer would be A.)12

Step-by-step explanation: You needed to find out what number you can put for it to add up to the number on the bottom line, 17. So you would add (12+5=17) , And you would get the same number as the number on the bottom line.

~hope this explanation has helped~

6 0

3 years ago

Rezolvati in multimea numerelor intregi ecuatiile:3(19-x)=4x-13

Hitman42 [59]

What language is this in because I don't understand any of it?

6 0

3 years ago

Please help basic Algebra.

Tasya [4]

Susanne will be x because both people use her as a comparsion. Bob's expression would be 4x, and Dakota's expression would be x - 3. If Dakota's and Bob's age sum is 93 then form the equation 4x + x - 3 = 93 to find Susanne's age. I'll do the steps below.

4x + x - 3 = 93

5x - 3 = 93

5x = 96

x = 19.2

8 0

3 years ago

Jamal draws triangle XYZ. If angle X=46 degrees, XZ = 10 degrees, and YZ=8 degrees, what is the approximate length of XY?

Mashutka [201]

In triangle XYZ,
angle X=46 degrees,
XZ = 10 units and
YZ=8 units.

We will find the length of XY using cosine rule:

According to cosine rule:

a² = b² + c² - 2bc cosA (the figure is attached)
Here, A = 46 degree.
a = 8 units.
b = ?
c = 10 units.
⇒ b² = c² - a² -2bc cosA
⇒ b² = 100 - 64 - 160*cos(46)
⇒ b² = 100 - 64 - 160*0.69
⇒ b² = 100 - 64 - 110.4
⇒ b² = 100 - 64 - 110.4
⇒ b² = 74.4
or b = 8.62 units.
or b = 8 untis approximately.

5 0

3 years ago

Read 2 more answers

Jane’s buying clothes. She can get 5 shirts & 4 sweaters for $229 or she can get 2 shirts & 3 sweaters for $128. How muc

makkiz [27]

Cost of 1 shirt is $\$25$ and cost of one sweater is $\$26$

Solution:

Given that Jane’s buying clothes.

She can get 5 shirts & 4 sweaters for $\$229$

She can get 2 shirts & 3 sweaters for $\$128$

Need to determine cost of 1 shirt and 1 sweater.

Let assume cost of 1 shirt = $\$x$

And assume cost of 1 sweater = $\$y$

Let us create equations from give conditions

First condition is Cost of 5 shirt + cost of 4 sweater = $\$229$

$\begin{array}{l}{\text { cost of 5 shirts }=5 \times \text { cost of 1 shirt }=5 \times x=5 x} \\\\ {\text { cost of 4 sweater }=4 \times \text { cost of 1 sweater }=4 \times y=4 y}\end{array}$

So using first condition equation which we get is as follows

$5 x+4 y=229 \rightarrow (1)$

Second condition is Cost of 5 shirt + cost of 4 sweater = $\$128$

$\begin{array}{c}{\text { cost of } 2 \text { shirts }=2 \times \text { cost of } 1 \text { shirt }=2 \times x=2 x} \\\\ {\text { cost of } 3 \text { sweater }=3 \times \text { cost of } 1 \text { sweater }=3 \times y=3 y}\end{array}$

So using second condition equation which we get is as follows

$2 \mathrm{x}+3 \mathrm{y}=128\quad\rightarrow (2)$

Now we have two equations to be solved

$\begin{array}{l}{5 x+4 y=229 \rightarrow (1)} \\\\ {2 x+3 y=128 \rightarrow (2)}\end{array}$

On multiplying equation (1) by 2 and equation (2) by 5 to make coefficients of x equal in both equations, we get

$\begin{array}{l}{2 x(5 x+4 y)=2\times 229} \\\\ {10 x+8 y=458 \rightarrow (3)} \\\\ {5 x(2 x+3 y)=5 \times 128} \\\\ {10 x+15 y=640 \rightarrow (4)}\end{array}$

On subtracting (3) from (4), we get

$\begin{array}{l}{(10 \mathrm{x}-10 \mathrm{x})+(15 \mathrm{y}-8 \mathrm{y})=640-458} \\\\ {\Rightarrow 7 \mathrm{y}=182} \\\\ {\Rightarrow \mathrm{y}=\frac{182}{7}=26}\end{array}$

On substituting y = 26 in equation (1) we get

$\begin{array}{l}{\Rightarrow 5 \mathrm{x}+(4 \times 26)=229} \\\\ {\Rightarrow 5 \mathrm{x}=229-104} \\\\ {\Rightarrow 5 \mathrm{x}=125} \\\\ {\Rightarrow \mathrm{x}=\frac{125}{5}=25}\end{array}$

Cost of 1 shirt = $\$x = \$25$

Cost of 1 sweater = $\$y = \$26$

7 0

3 years ago