Answer: 0.22
Step-by-step explanation:
Answer:
The growth rate for the period was of 17.86%.
Step-by-step explanation:
To find the growth rate as a percent, we multiply the change by 100, and divide by the initial value.
A house cost $112,000 in 2010. By the year 2015, the house had a value of $132,000.
Change: 132 - 112 = 20
Initial value: 112
Growth rate as a percent:
20*100/112 = 17.86%
The growth rate for the period was of 17.86%.
Answer:
<em>the unit rate is 0.8x per unit y</em>
<em></em>
Step-by-step explanation:
the proportional relationship is y = 
this means that the constant of proportionality k = 
= 0.8
re-writing, we have
<em>y = 0.8x</em>
<em>therefore, the unit rate is 0.8x per unit y</em>
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
Answer:
k&F 20 degrees
Step-by-step explanation:
hope it helps
