1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bezzdna [24]
3 years ago
8

An image formed by a circular spotlight has a radius of 124 centimeters. What is the area of the circular image? Use 3.14 for pi

().
Mathematics
2 answers:
Tema [17]3 years ago
6 0

Answer:

Area of circle  = 48280.64 cm².

Step-by-step explanation:

Given  : An image formed by a circular spotlight has a radius of 124 centimeters.

To find : What is the area of the circular image.

Solution : We have given that radius = 124 cm.

Area of circle  =  pi * ( radius)².

Plug pi = 3. 14 and radius  = 124 cm.

Area of circle  =  3.14 * ( 124)².

Area of circle  =  3.14  * 15376.

Area of circle  = 48,280.64 cm².

Therefore, Area of circle  = 48280.64 cm².

Lemur [1.5K]3 years ago
5 0

area = pi X radius squared

 so area = 3.14 x 124^2

= 3.14 x 15376 = 48,280.64 square centimeters.

You might be interested in
The product of two numbers is 20. If one the numbers is 5/12 what is the other number
Zepler [3.9K]

Answer:

48.

Step-by-step explanation:

Let's write a simple equation. Let x = other number, then

5/12 * x = 20

x = 20 / 5/12

x = 20 * 12 / 5

x = 4 * 12 = 48  (answer)


3 0
3 years ago
Lara wrote the statements shown in the chart below:
Brums [2.3K]

Answer:

Option 4:

Statement 1 and Statement 2 are theorems because they can be proved.


7 0
3 years ago
Read 2 more answers
Alex and Leonardo purchase to matinee movie tickets mantiee ticket cost $6.50 and drinks cost $5.50 and a bag of popcorn cost $6
Veseljchak [2.6K]
Cost= (5.50d+6.00p) +6.50

Coefficients: 5.50 and 6.00
Constant: 6.50
Variables: d and p
6 0
3 years ago
A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee
madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

nC_r=\frac{n!}{r!(n-r)!}

Using the formula

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

5 0
3 years ago
I need help plez and thanks
Brilliant_brown [7]
He has a total of $58.19.
1 day = $2.74

58.19/2.74 
21.24

You can't have 21.2 days, so you need to round down to 21.

Jim can buy lunch for 21 days before he runs out of money on his account.
3 0
3 years ago
Read 2 more answers
Other questions:
  • Laminate buys 12 packs of juice and pays a total of $48. Use a ratio table to determine how much she will pay to buy 8 more pack
    12·1 answer
  • John starts a saving account with $100. Every week he adds $6 to his account. Which equation can be used to determine the number
    9·1 answer
  • I really need help on this question!!!
    8·2 answers
  • Solve for N<br>4 + N = 8x5<br>​
    6·1 answer
  • Which data set has an apparent negative, but not perfect, linear relationship between its two variables
    7·1 answer
  • 3. Circle the smallest number.<br> -2.5 and 1.5<br> Plss answers
    5·2 answers
  • Convert 5 ounces into kilograms. Round your answer to the nearest hundredth.
    11·2 answers
  • Someone please help me with number 4
    12·1 answer
  • IF YOU GOOD AT MATH PLZ HELP !!! Algebra II <br><br> Answer:???
    6·1 answer
  • What are the solutions to the quadratic equation 0=(x−4)(x+2)?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!