Question

PLZ HELP ASAP TANGENTS OF CIRCLES

Answer 1

First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O. 
 
    m∠O = 2 (65°) = 130°

Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°. 

     m∠O + m∠C + m∠B + m∠A = 360°

Substituting the known values,
     130° + 90° + 90° + m∠A = 360°

The value of m∠A is equal to 50°.

Answer: 50°