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alexandr1967 [171]

3 years ago

5

What is the difference between the weight of 5.595.59 lb and the mean of the weights? b. How many standard deviations is that

[the difference found in part (a)]? c. Convert the weight of 5.595.59 lb to a z score. d. If we consider weights that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the weight of 5.595.59 lb significant?

1 answer:

icang [17]3 years ago

6 0

They weight different

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What is 2.26 (26 repeating)as a fraction

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Please answer this question

max2010maxim [7]

<h3>━━━━━━❃━━━━━━</h3>

<h3>Part one :</h3>

As it is given :

Present age of mom : Present age of son = 6 : 1

Therefore let :

Mother's age be 6x

Son's age be x

<h3>Part two :</h3>

Ages after 10 year :

Mom's age = 6x + 10

Son's age = x + 10

<h3>Part three :</h3>

The ages after 10 years are given in rational of 8 : 3.

Which means :

Mom's age after 10 years : Son's age after 10 years = 8 :3.

Now :

$\scriptsize \purple{ \boxed{ \scriptsize \dfrac{ \text{Mom's age after 10 years}}{ \text{son's age after 10 years}}= \dfrac{8}{3} }} \star$

$\\ \\$

So :

$\small\sf \dashrightarrow \dfrac{6x + 10}{x + 10} = \sf \dfrac{8}{3}$

$\\ \\$

$\small\sf \dashrightarrow \dfrac{3(6x + 10)}{x + 10} = \sf \dfrac{8}{1}$

$\\ \\$

$\small \sf \dashrightarrow \dfrac{18x +30}{x + 10} = \sf \dfrac{8}{1}$

$\\ \\$

$\small\sf \dashrightarrow \dfrac{18x +30}{1} = \sf \dfrac{8(x + 10)}{1}$

$\\ \\$

$\small \sf \dashrightarrow 18x +30= \sf 8(x + 10)$

$\\ \\$

$\small\sf \dashrightarrow 18x +30= \sf 8x + 80$

$\\ \\$

$\small\sf \dashrightarrow 18x - 8x +30= \sf 80$

$\\ \\$

$\small \sf \dashrightarrow 10x +30= \sf 80$

$\\ \\$

$\small \sf \dashrightarrow 10x = \sf 80 - 30$

$\\ \\$

$\small \sf \dashrightarrow 10x = \sf 50$

$\\ \\$

$\small \sf \dashrightarrow \dfrac{10x}{10} = \sf \dfrac{50}{10}$

$\\ \\$

$\small \sf \dashrightarrow \dfrac{1\cancel0x}{1\cancel0} = \sf \dfrac{5\cancel0}{1\cancel0}$

$\\ \\$

$\small\bf \dashrightarrow x = \pink 5$

$\\$

<h3>Part four :</h3>

We know :

$\footnotesize \hookrightarrow \sf Son's \: age = x$

$\footnotesize \hookrightarrow \sf Son's \: age = \red{5 \: years}$

$\\ \\$

$\footnotesize \hookrightarrow \sf Mother's \: age = 6x$

$\footnotesize\hookrightarrow \sf Mother's \: age = 6 \times 5$

$\footnotesize \hookrightarrow \sf Mother's \: age = \bf \red{30 \: years}$

<h3>━━━━━━❃━━━━━━</h3>

And all we are done ! ㋛

<h3>~ $\pmb{\cal W\frak{indy}M\frak{int}}$ ༄</h3>

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andreyandreev [35.5K]

Answer:

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Step-by-step explanation:

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UkoKoshka [18]

Answer:

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Step-by-step explanation:

8x-y²-3

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-2 - (9) - 3

= -14

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