Question

A typical middle-income household in 1980 earned $34,757. A similar household in 2009 earned $38,550. What was the relative increase in income for these households from 1980 to 2009? Round to the nearest one percent.

Answer 1

Given conditions are :

In 1980's, a typical middle-income household earned=  $34,757

In 2009, a similar middle-income household earned= $38,550

And we have to find relative increase in income for these households from 1980 to 2009.

So first we will find the total increase in amounts.

$38550-34757=3793$

Relative increase = $\frac{3793}{34757}*100$

= 10.91% or rounding it off we get approx 11%.

Hence, the answer is 11%.

Answer 2

Answer:

The relative increase in income for these households from 1980 to 2009 is:

                                         11%

Step-by-step explanation:

If the initial amount is : a

and the increased amount the other year is: b

Then the relative increase is calculated by:

$\dfrac{b-a}{a}$

and in percent we calculate it as:

$\dfrac{b-a}{a}\times 100$

Here ,

A typical middle-income household in 1980 earned $34,757.

i.e.  a=$  34,757

A similar household in 2009 earned $38,550.

i.e. b=$ 38,550

then the relative increase in percent from 1980 to 2009 is:

$=\dfrac{38,550-34,757}{34757}\times 100\\\\\\=\dfrac{3793}{34757}\times 100\\\\\\=0.1091291\times 100\\\\=10.91291\%$

Now, on rounding to the nearest percent we have:

Relative increase= 11%