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3 years ago

What is the value of 6x^3 +8x when x = 5

Mathematics

2 answers:

sertanlavr [38]3 years ago

6 0

Just sub x in with 5.
So 6(5)^3+8(5) = 6 (125) + 40 = 750 + 40 = 790.
So 790

Vsevolod [243]3 years ago

5 0

6 (5^3)+8
5*5*5
*6
+8
So your answer if you're evaluating is 758

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Ierofanga [76]

Answer:

see below

Step-by-step explanation:

m/3 + 4 = 7

Subtract 4 from each side

m/3+4-4 = 7-4

m/3 = 3

Multiply each side by 3

m/3*3 = 3*3

m =9

4 0

3 years ago

On August 1, 2021, a company accepts an $8,000, 9-month note receivable. For 2021, the company reports interest revenue of $200.

erastova [34]

Answer:

Step-by-step explanation:

We have to calculate the interest rate in the note, we must follow the following steps, calculate the amount of time remaining from the year 2021, as follows:

interest is for 5 months i.e. from Aug 01 to Dec 31 for year 2021 , so it means it would be 5/12 months.

We have to calculate the interest as follows:

I = P * R * T

We replace:

200 = 8000 * R * 5/12

we solve for R

200 * 12/5 = 8000 * R

R * 8000 = 480

R = 480/8000

R = 0.06

Which means that the interest rate on the note is 6%

4 0

3 years ago

Name a pair of Alternate Exterior Angles

pogonyaev

Answer:

M, Z

O, X

P, W

N, Y

Step-by-step explanation:

They are all Alternate Exterior Angles.

<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!</em>

4 0

2 years ago

Read 2 more answers

If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?

oksano4ka [1.4K]

$\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given $\boxed{ \ a(x) = 3x + 1 \ }$ and $\boxed{ \ b(x) = \sqrt{x - 4} \ }$ .

We will form (b o a)(x) and then determine the domain.

$\boxed{ \ (b \circ a)(x) = b(a(x)) \ }$

Replace each appearance of x in b(x) with $\boxed{ \ a(x) = 3x + 1 \ }$ .

$\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }$

Thus, $\boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }$

To be defined, the value under the radical sign must not be negative. Therefore, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ are processed as follows.

$\boxed{ \ 3x - 3 \geq 0 \ }$

Both sides added by 3.

$\boxed{ \ 3x \geq 3 \ }$

Both sides divided by 3.

$\boxed{ \ x\geq 1 \ }$

Thus, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ is $\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Learn more</h3>

If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
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Look for rotation rules in the transformation brainly.com/question/2992432

Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,

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4 years ago

Read 2 more answers

Find the quotient 4/5 ÷3

Deffense [45]

$\frac{4}{5}$ divided by 3 = 4/15

Hope I Helped

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3 years ago

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