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3 years ago

12

An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. It flies up to its nest in a tree at a height of 25 m. How much

gravitational potential energy did the eagle gain?

2 answers:

erma4kov [3.2K]3 years ago

4 0

Answer: 882 J

Explanation:

Correct on E2020

Anuta_ua [19.1K]3 years ago

3 0

Answer:

900 J

Explanation:

Given, mass of eagle, m=4.5 kg

Initial height , $h_1=5\ m.$

Final height , $h_2=25\ m.$

Gain in height= $h_2-h_1=25-5\ m=20\ m.$

We know Gravitational potential energy of an object is given as $Mgh .$

Here , g is acceleration due to gravity=9.8 $m/s^2.$

M is mass of object.

h is height of object.

Now, gain in potential energy = $m\times g\times h=4.5 \times 20 \times 10 \ J=900 \ J.$

Therefore , this is the required solution.

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Tony completed a 720 km journey with an average speed of 90 km/h for the first 285 km he travelled at an average speed of 95 Km/

sp2606 [1]

Answer:

$Speed = 87 km/h$

Explanation:

Given

Total Distance = 720km

Average Speed = 90km/h

Average Speed (285km) = 95km/h

Required

Determine the average speed for the rest of the journey

First we need to determine the time taken to complete the journey using

$Speed = \frac{Distance}{Time}$

$90 = \frac{720}{Time_1}$

Make Time the subject of formula

$Time_1 = \frac{720}{90}$

$Time_1 = 8 hour$

Next, we determine the time taken to complete 285km of the journey using

$Speed = \frac{Distance}{Time}$

$95 = \frac{285}{Time_2}$

Make Time the subject of formula

$Time_2 = \frac{285}{95}$

$Time_2 = 3 hours$

The difference between these calculated times is the time taken to complete the rest of the journey

$Time = Time_1 - Time_2$

$Time = 8\ hour - 3\ hour$

$Time = 5\ hour$

Also, we need to calculate the distance of the rest of the journey

$Distance = 720\ km - 285\ km$

$Distance = 435\ km$

The average speed can then be calculated;

$Speed = \frac{Distance}{Time}$

$Speed = \frac{435}{5}$

$Speed = 87 km/h$

<em>Hence, the average speed of the rest of the journey is 87km/h</em>

3 0

3 years ago

An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th

stepan [7]

Answer:

Number of photons travel through pin hole= $6.4*10^{17}$

Explanation:

First we will calculate the energy of single photon using below formula:

$E=\frac{h*c}{λ}$

Where :

h is plank's constant with value $6.626*10^{-34} J.s$

c is the speed of light whch is $3*10^{8}$

λ is the wave length = 532nm

$E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}$

E= $3.73*10^{-19}$ J

Number of photons emitted per second:

$\frac{5J/s}{1 photon/3.73*10^{-19} }$

Number of photons emitted per second= $1.34*10^{19} photons/s$

$\frac{A-hole}{A-beam}$ = $\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }$

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

$\frac{A-hole}{A-beam}$ = $\frac{d-hole^2}{d-beam^2}$

$\frac{Ahole}{A-beam}$ = $\frac{1.22^2}{5.5^2}$

$\frac{A-hole}{A-beam}$ = $\frac{144}{3025}$

Number of photons travel through pin hole= $1.34*10^{19} *\frac{144}{3025}$

Number of photons travel through pin hole= $6.4*10^{17}$

7 0

3 years ago

What is the acceleration given to a 50-kg block of cement when it is pulled

melomori [17]

the answer is a= 16m/s2

you can use the formula f=m*a to solve this bb :)

3 0

4 years ago

Read 2 more answers

A 5000-lb truck is being used to lift a 1000 lb boulder B that is on a 200 lb pallet A. Knowing the acceleration of the truck is

vova2212 [387]

Answer:

Part a: The force between the tires and the ground is 765 lbf.

Part b: The force between the pallet and the boulder is 1016 lbf.

Explanation:

From the free body diagram on the Truck, boulder and pallet level

$a_T$ is the acceleration of truck which is 1 ft/s2
$m_T$ is the mass of the truck which is 5000 lb or 155.28 slugs

$m_b$ is the mass of the boulder which is 1000 lb or 31.06 slugs

$m_a$ is the mass of the pallet which is 200 lb or 6.211 slugs
$a_a =a_b$ is the acceleration of the pallet or boulder which is 0.5 ft/s2

Applying Newton's 2nd Law of Motion on pulley in vertical direction

$2T-(m_a+m_b)g=(m_a+m_b)a_a\\2T-(37.271)(32.2)=(37.271)(0.5)\\T=609.32 lb_f$

Part a

Applying Newton's 2nd Law of Motion on Truck in horizontal direction

$F-T=m_Ta_T\\F=609.32+(155.28)(1)\\F=765 lb_f$

So the force between the tires and the ground is 765 lbf.

Part b

Applying Newton's 2nd Law of Motion on Boulder in vertical direction

$F_{AB}-m_bg=m_ba_b\\F_{AB}=m_b(g+a_b)\\F_{AB}=31.056(32.2+0.5)\\F_{AB}=1016 lb_f$

So the force between the pallet and the boulder is 1016 lbf.

4 0

4 years ago

A car starts from rest and after 7 seconds it is moving at 42 m/s. what is the carâs average acceleration?

Lesechka [4]

<span> a= (v2 - v1) / (t2 - t1)
a = (42-0)/ (7-0)

42/7 = 6

a(avrg.)= 6 m/s(sqaured)
i hope this is right, i tried if its wrong, i truly did try!!
</span>

6 0

4 years ago